See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let x be the amount of water and y be the amount of ice at the end of second minute ice water yL (x y)C T 30 60      400y (x y)4 2 1800     …(i) (x y) 4 6 30 60      …(ii) Solving (i) and (ii) 1800 400y 2 1800 6    400y = 1200  y = 3g Initial amount of ice = 30 120 3 12g 400   