Calculate the I—I distance in () for given compound if C—I bond length is . ()

Question

Calculate the I—I distance in ($	ext{\AA}$) for given compound $H_2CCI_2$ if C—I bond length is $2.35 	ext{ \AA}$. ($\sin 60^\circ = 0.866$)

Prashant Kotian · Accepted Answer

Correct answer: 4

**SOLUTION:** $H_2C = CI_2$, HAS $SP^2$ HYBRIDISED CARBON AND THUS $I - C - I$ BOND ANGLE IS $120^\CIRC$.
[IN $\TRIANGLE ICO, \ANGLE ICO = 60^\CIRC$ AND $\ANGLE IOC = 90^\CIRC$]
$IO = CI \SIN 60^\CIRC = 2.35 \TIMES 0.866 = 2.0351 \TEXT{ \AA}$
$I - I \TEXT{ DISTANCE} = 2.0351 \TIMES 2 = 4.07 \TEXT{ \AA} \APPROX 4$. Step 1: Noble gases exist as monoatomic, completely non-polar neutral atoms with symmetrical electron clouds. Step 2: Because they lack any permanent dipoles or charges, they cannot interact via ion-dipole or dipole-induced dipole forces. Step 3: The only intermolecular attractions that can exist between monoatomic noble gas atoms are temporary, fluctuating dipoles known as London dispersion forces. Thus, option (d) is correct.

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