See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 0 0 1 2 F F a sin t sin t R sin t m m             2 2 0 0 2 2 F F a cos t cos t Rcos t m m             Here 0 2 F R m     0 0 1 2 F F v 1 cos t & v sin t m m             1 2 x R t sin t & y R 1 cos t       0 1 F v m   , and 2 v 0   26. No external force is acting along horizontal direction 27. E = U + K, for a given E, k will be maximum where U will be minimum. 28. Taking torque about A       s 2 mg cos f sin N cos 2 N2 B F2 A F1 mg fs FBD of Rod-2 F fs N2 N1 FBD of Rod-1       2 mg N 2 1 tan AITS-PT-I-PCM (Sol.)-JEE(Main)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7     s min smax 2 F f F f N                 min 2 mg