What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol–1) and the decrease in freezing point is 0.40 K? (A) 3.72 K kg mol–1 (B

Question

What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol–1) and the decrease in freezing point is 0.40 K?

(A) 3.72 K kg mol–1
(B) 1.86 K kg mol–1
(C) 4.43 K kg mol–1
(D) 5.12 K kg mol–1

Prashant Kotian · Accepted Answer

Correct answer: D. TF = KF.m 0.4 = KF     256 1 KF = 5.12 K. Kg/mole. | JEE(Main) 2025 | DATE : 28-01-2025 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 6

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