The equilibrium composition for the reaction PCl3 + CI2 PCI5 at 298 K is given below : [PCI3]eq = 0.2 mol L–1, [C2]eq = 0.1 mol L–1, [PCl5]eq = 0.40 mol L–1 If 0.2 mol of Cl2 is added at the same temp

Question

The equilibrium composition for the reaction PCl3 + CI2 PCI5 at 298 K is given below : [PCI3]eq = 0.2 mol L–1, [C2]eq = 0.1 mol L–1, [PCl5]eq = 0.40 mol L–1 If 0.2 mol of Cl2 is added at the same temperature, the equilibrium concentrations of PCl5 is______ ×10–2 mol L–1 Given: KC for the reaction at 298 K is 20

Prashant Kotian · Accepted Answer

Correct answer: .. PCl3(g) + Cl2(g) PCl5(g) At equilibrium 0.2 Lit Mole 0.1 Lit Mole 0.4 Mole/Lit New equilibrium (0.1 - x) (0.3 - x) (0.4 + x) KC =        . 2 . 4 . =          ) x . () x . ( x . = 20 = ) x . () x . ( x .    (2 – 20 x) (6 – 20 x) = 0.4 + x 12 – 120 x – 40 x + 40x2 = (0.4 + x) 40x2 – 159x + 11.6 = 0 x = 0.48

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