Given enthalpy of formation of (g) and (s) are -94.0 kJ and -152 kJ, respectively, and the enthalpy — Thermodynamics and Thermochemistry Chemistry Question
Question
Given enthalpy of formation of $CO_2$(g) and $CaO$(s) are -94.0 kJ and -152 kJ, respectively, and the enthalpy of the reaction: $CaCO_3$(s) -> $CaO$(s) + $CO_2$(g) is 42 kJ. The enthalpy of formation of $CaCO_3$(s) is
Answer: D
💡 Solution & Explanation
For the decomposition reaction: $CaCO_3$(s) -> $CaO$(s) + $CO_2$(g), δ H° = delta_f H°($CaO$, s) + delta_f H°($CO_2$, g) - delta_f H°($CaCO_3$, s). Given δ H° = 42 kJ, delta_f H°($CO_2$) = -94.0 kJ, delta_f H°($CaO$) = -152 kJ: 42 = -152 + (-94.0) - delta_f H°($CaCO_3$, s) => delta_f H°($CaCO_3$, s) = -246 - 42 = -288 kJ/mol.
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