See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

3 2 1 W 1 w 4 4 R . .g Ah. g R . .g Ah . g 3 3              1/3 1 w 1 2 w 3A h h 4            Using values A = 11 cm2; h1 = 4 cm; 3 w 1 gm / cm ;       3 3 1 2 1/3 3