Given below are two statements Statements-I : The number of paramagnetic species among [CoF6] 3–, [T — JEE Mains Chemistry Past Papers Chemistry Question
Question
Given below are two statements Statements-I : The number of paramagnetic species among [CoF6] 3–, [TiF6] 3–, V2O5 and [Fe(CN)6] 3– is 3. Statement-II : K4[Fe(CN)6] < K3[Fe(CN)6] < [Fe(H2O)6] SO4.H2O < [Fe(H2O)6]Cl3 is the correct order in terms of number of unpaired electron(s) in the complexes. In the light of the above statements, choose the correct answer from the options given below. (A) Both statement-I and statement-II are true (B) Both statement-I and statement-II are false (C) Statement-I is true but statement-II is false (D) Statement-I is false but statement-II is true
💡 Solution & Explanation
Paramagnetic species : [CoF6] 3–, [TiF6] 3–, [Fe(CN)6] 3– Diamagnetic species : V2O5 In K4[Fe(CN)6] No. of unpaired electron = 0 K3[Fe(CN)6] No. of unpaired electron = 1 [Fe(H2O)6]SO4.H2O No. of unpaired electron = 4 [Fe(H2O)6]Cl3 No. of unpaired electron = 5