JEE Mains Chemistry Past PapershardMCQ SINGLE

Given below are two statements Statements-I : The number of paramagnetic species among [CoF6] 3–, [TJEE Mains Chemistry Past Papers Chemistry Question

Question

Given below are two statements Statements-I : The number of paramagnetic species among [CoF6] 3–, [TiF6] 3–, V2O5 and [Fe(CN)6] 3– is 3. Statement-II : K4[Fe(CN)6] < K3[Fe(CN)6] < [Fe(H2O)6] SO4.H2O < [Fe(H2O)6]Cl3 is the correct order in terms of number of unpaired electron(s) in the complexes. In the light of the above statements, choose the correct answer from the options given below. (A) Both statement-I and statement-II are true (B) Both statement-I and statement-II are false (C) Statement-I is true but statement-II is false (D) Statement-I is false but statement-II is true

Answer: A

💡 Solution & Explanation

Paramagnetic species : [CoF6] 3–, [TiF6] 3–, [Fe(CN)6] 3– Diamagnetic species : V2O5 In K4[Fe(CN)6]  No. of unpaired electron = 0 K3[Fe(CN)6]  No. of unpaired electron = 1 [Fe(H2O)6]SO4.H2O  No. of unpaired electron = 4 [Fe(H2O)6]Cl3  No. of unpaired electron = 5

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