Arrange the following orbitals in decreasing order of energy. A. n = 3, l = 0, m = 0 B. n = 4, l = 0, m = 0 C. n = 3, l = 1, m = 0 D. n = 3, l = 2, m = 1 The correct option for the order is : (A) D

Question

Arrange the following orbitals in decreasing order of energy. A. n = 3, l = 0, m = 0 B. n = 4, l = 0, m = 0 C. n = 3, l = 1, m = 0 D. n = 3, l = 2, m = 1 The correct option for the order is :

(A) D > B > C > A
(B) B > D > C > A
(C) A > C > B > D
(D) D > B > A > C

Prashant Kotian · Accepted Answer

Correct answer: A. In multi electronic species energy is decided on the basis of (n + l) rule. So increasing order of energy is 3d > 4s > 3p > 3s

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