In the outer space, the pressure recorded is 5 * 10^-4 torr. How much outer space could be compresse — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Using Boyle's law: P1 * V1 = P2 * V2. Given: P1 = 5 * 10^-4 torr, P2 = 1 atm = 760 torr, V2 = 1 dm^3. V1 = (P2 * V2) / P1 = (760 * 1) / (5 * 10^-4) = 1.52 * 10^6 dm^3.