Five moles of an ideal gas expand isothermally and reversibly from an initial pressure of 100 atm to a final pressure of 1 atm at 27°C. The work done by the gas is (ln 100 = 4.6)

Question

Prashant Kotian · Accepted Answer

Correct answer: D. Work done BY the gas in an isothermal reversible expansion is given by W_by_gas = nRT ln(P1/P2) = 5 * R * 300 * ln(100). Taking R = 2 cal/K-mol: W_by_gas = 5 * 2 * 300 * 4.6 = 13,800 cal.

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