Consider the following reactions K2Cr2O7 O H KOH [A] O H SO H 4 [B] + K2SO4 The products [A] and [B] — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

K2Cr2O7 O H – KOH    (A) 2 CrO K O H – SO H 4 2      (B) 2 O Cr K + K2SO4 The chromates and dichromate are inter convertible in aq. solution depending upon pH of solution. Cr2O72– + 2OH– 2Cr2O72– + H2O 2CrO42– + 2H+ Cr2O72– + H2O