See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

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Answer: 6

💡 Solution & Explanation

N B B N B N X H H H H H (Y has 3 different positions) N B B N B N Y H H H H H (X has 3 different positions) Total position isomers = 3 + 3 = 6.

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