A complex with the composition [MA3B]^{n\pm} is found to have no geometrical isomers. The possible s — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: Analyze the spatial arrangements for a four-coordinate complex of type [MA3B]. Step 2: In a tetrahedral structure, all four positions are adjacent, meaning no geometrical isomers can exist. In a square planar structure, the single ligand B is always adjacent (90°) to two A ligands and opposite (180°) to one A ligand, also resulting in only a single possible spatial arrangement with no geometrical isomers. Step 3: Thus, both tetrahedral and square planar structures of [MA3B] have no geometrical isomers, matching option (c).