A quantity of 4 g of oxygen occupies 10 l at a particular pressure and temperature. If the pressure — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

from pv = nrt, v is constant, so n2 = (p2/p1) × (t1/t2) × n1. given p2 = 2 × p1 and t2 = t1 / 2. n2 = 2 × 2 × n1 = 4 × n1. since mass is ∝ moles, the required final mass of o2 is 4 × 4 g = 16 g. therefore, the mass of gas to be added is 16 - 4 = 12 g.