JEE Mains Chemistry Past PapershardNUMERICAL

The number of atoms in 8 g of sodium is x × 1023. The value of x is ………………. . (Nearest integer) [GivJEE Mains Chemistry Past Papers Chemistry Question

Question

The number of atoms in 8 g of sodium is x × 1023. The value of x is ………………. . (Nearest integer) [Given: NA = 6.02 × 10 mol–1, Atomic mass of Na = 23.0 u] 8 g lksfM;e esa ijek.kqvksa dh la[;k x × 1023 gSA x dk eku gS ……………….A (fudVre iw.kk±d esa) [fn;k gS % NA = 6.02 × 10 mol–1, Na dk ijek.kq nzO;eku = 23.0 u]

Answer: .

💡 Solution & Explanation

Number of mole of sodium =     8 Number of sodium atom =     8 × 6 × 1023 = 2.08 × 1023 | JEE MAIN-2021 | DATE : 01-09-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAER | CHEMISTRY PAGE # 9

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