Two moles of an ideal gas [ (J/K-mol) = 20 + 0.01 T] is heated at constant pressure from 27°C to 127°C. The amount of heat absorbed by the gas is

Question

Two moles of an ideal gas [$C_{v,m}$ (J/K-mol) = 20 + 0.01 T] is heated at constant pressure from 27°C to 127°C. The amount of heat absorbed by the gas is

Prashant Kotian · Accepted Answer

Correct answer: C. = + R = (20 + 0.01 T) + 8.314 = 28.314 + 0.01 T J/K-mol. Heat absorbed at constant pressure is q_p = n * int_{T1}^{T2} dT = 2 * int_{300}^{400} (28.314 + 0.01 T) dT = 2 * [28.314 * (400 - 300) + 0.005 * (400^2 - 300^2)] = 2 * [2831.4 + 0.005 * 70000] = 2 * [2831.4 + 350] = 2 * 3181.4 = 6362.8 J.

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