See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. (for Q. 29 – 31): (I) Isothermal expansion (II) Water & Ice will remain in equilibrium to 0°C & 1 atm pressure so ΔG=0 (III) For adiabatic reversible 2/5 1 1 2/5 1 2 2 1 1 2 2 10 T 300 300 120 1 P P T P T K P                          For adiabatic irreversible 2 1 v 2 1 ext 2 1 2 2 1 nRT nRT C (T -T )=-P (V -V )=-P - P P       AITS-FT-V (Paper-1)-PCM(Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 v 2 1 2 1 2 2 1 2 1 1 2 2 1 2 2 1 1 2 C T T (T -T ) = -P - nR P P (T -T ) T P =-T + γ-1 P P (γ-1) 1 T =T + γ P γ T =192K             (IV) Mixing of ideal gas at constant T & P in an isolated container 0, 0, U 0, 0, 0 system q w S G          SECTION – B