The half-life of radioisotopic bromine - 82 is 36 hours. The fraction which remains after one day is — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Half life of bromine – 82 = 36 hours 1/2 0.693 t K  0.693 K  = 0.01925 hr–1 1st order rxn kinetic equation 2.303 a t log K a x   a t K log a x 2.303    (t = 1day = 24hr) a 24hr 0.01925hr log a x 2.303     a log 0.2006 a x     a antilog 0.2006 a x   a 1.587 a x   If a = 1 1.587 x    1 – x = 0.6301 = Fraction remain after one day $//(1® Final JEE-Main Exam January, 2024/29-01-2024