The potential for the given half cell at 298K is (-)………… × 10-2 V. 2H+ (aq) + 2e- H2 (g) [H+] = 1M, — JEE Mains Chemistry Past Papers Chemistry Question
Question
The potential for the given half cell at 298K is (-)………… × 10-2 V. 2H+ (aq) + 2e- H2 (g) [H+] = 1M, H P = 2 atm (Given: 2.303 RT/F = 0.06 V, log2 = 0.3)
Answer: .
💡 Solution & Explanation
2 H o H /H P 0.06 E = E log [H ] 0.06 E = 0.00 log [1] E = 0.03 0.3 0.9 10 V
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