The potential for the given half cell at 298K is (-)β¦β¦β¦β¦ Γ 10-2 V. 2H+ (aq) + 2e- H2 (g) [H+] = 1M, β JEE Mains Chemistry Past Papers Chemistry Question
Question
The potential for the given half cell at 298K is (-)β¦β¦β¦β¦ Γ 10-2 V. 2H+ (aq) + 2e- H2 (g) [H+] = 1M, H P = 2 atm (Given: 2.303 RT/F = 0.06 V, log2 = 0.3)
Answer: .
π‘ Solution & Explanation
2 H o H /H P 0.06 E = E log [H ] ο« ο« ο 0.06 E = 0.00 log [1] ο E = 0.03 0.3 0.9 10 V ο ο ο΄ ο½ο ο΄
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes