The ionic product of water is 1.0 * 10^-14 at 25°C. Assuming the density of water independent from c — Ionic Equilibrium Chemistry Question
Question
The ionic product of water is 1.0 * 10^-14 at 25°C. Assuming the density of water independent from change in temperature, the ionic product of water at 50°C will be
Answer: C
💡 Solution & Explanation
Auto-ionization of water is an endothermic reaction. According to Le Chatelier's principle, increasing the temperature will shift the equilibrium forward, causing an increase in [H+] and [OH-]. Consequently, Kw at 50°C must be greater than 1.0 * 10^-14. The only value significantly larger is 5.9 * 10^-14.
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