The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω . If the con — Electrochemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Identify the relevant formula** The relationship between conductivity (κ), resistance (R), and cell constant (G*) is: G* = κ × R where: - κ = conductivity (S cm⁻¹) - R = resistance (Ω) - G* = cell constant (cm⁻¹) **Step 2: Convert conductivity to standard units** κ = 0.152 × 10⁻³ S cm⁻¹ = 1.52 × 10⁻⁴ S cm⁻¹ **Step 3: Identify given values** - R = 1750 Ω - κ = 1.52 × 10⁻⁴ S cm⁻¹ **Step 4: Calculate cell constant** G* = κ × R G* = (1.52 × 10⁻⁴ S cm⁻¹) × (1750 Ω) G* = 2.66 × 10² cm⁻¹ G* = 266 cm⁻¹ **Step 5: Express in required form** The cell constant is 266 × 10⁰ cm⁻¹, or simply 266.00 cm⁻¹ Therefore, the answer is 266.00.