Isomerism and StereochemistryhardMCQ SINGLE

See imageIsomerism and Stereochemistry Chemistry Question

Question

See image

Chemistry diagram for: See image
Answer: A

💡 Solution & Explanation

Enol content in 1,2-diketones and 1,3-diketones (and related beta-diketones) depends on several factors: (1) stability of the enol form through intramolecular hydrogen bonding and conjugation, (2) ring strain relief upon enolization, (3) steric and geometric constraints. Step 1 - Identify the structures: - Structure I: Bicyclo[4.4.0]decane-4a,8a-dione (decalin-1,8-dione) — two six-membered rings fused at the junction bearing the two carbonyl groups. The two carbonyls are at the bridgehead/adjacent positions, forming a 1,2-diketone in a 6-6 fused system. - Structure II: Bicyclo[4.3.0]nonane-3a,7a-dione (hydrindane dione) — six-membered and five-membered rings fused, with the two carbonyls at the ring junction (1,2-diketone in a 6-5 fused system). - Structure III: Bicyclo[2.2.1]heptane-2,3-dione (norbornane-2,3-dione) — a highly strained bridged bicyclic system with adjacent diketone. Step 2 - Enol content considerations: For 1,2-diketones (alpha-diketones) in cyclic systems, enolization is favored when: the resulting enol can be stabilized, and when the geometry of the ring allows favorable overlap. The ring size and fusion geometry play critical roles. Step 3 - Effect of ring size and angle strain: - In structure I (6-6 fusion): The two six-membered rings provide a relatively relaxed geometry. The alpha-diketone at the ring junction can enolize; the enol benefits from conjugation with the adjacent carbonyl. The C-H alpha to the diketone is accessible. - In structure II (6-5 fusion): The five-membered ring introduces more angle strain and the carbonyl-carbonyl system is slightly more strained geometrically. Enolization is somewhat more favorable because the five-membered ring carbonyl is more reactive and the enol is stabilized. - In structure III (norbornane): The bridged bicyclic system with a 2,3-diketone is highly strained. The Bredt's rule-like constraints mean the enol double bond would be at a bridgehead-adjacent position but is not bridgehead itself, so it is accessible. However, the highly strained system actually disfavors enolization because the geometry required for enol formation is constrained, and the resulting enol would introduce additional strain. Step 4 - The key principle for decreasing enol content: The enol content is greatest where: the alpha-carbon has the most acidic H AND the enol form is most stabilized. For these alpha-diketones in cyclic systems, the 6-6 fused system (I) provides the best geometry for enol stabilization with an extended conjugated system and least strain in the enol. The 6-5 fused system (II) is intermediate. The norbornane system (III) has the most geometric constraint, making enol formation least favorable. Thus: I > II > III Why other options fail: - Option (b) II > I > III: Incorrect because the 6-6 system (I) is more favorable for enolization than the 6-5 system (II) due to better geometric overlap and less strain in the enol form. - Option (c) III > II > I: Incorrect; the strained bridged system has the least enol content. - Option (d) II > III > I: Incorrect for the same reasons. Therefore, the correct answer is A.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry