JEE Mains Chemistry Past PapershardMCQ SINGLE

At temperature T, compound AB2(g) dissociates as AB2(g) AB(g) + 2 1 B2(g) having degree of dissociatJEE Mains Chemistry Past Papers Chemistry Question

Question

At temperature T, compound AB2(g) dissociates as AB2(g) AB(g) + 2 1 B2(g) having degree of dissociation x (small compared to unity). The correct expression for x in terms of Kp and p is: (A) 3 p p K (B) p K (C) 4 p p K (D) 3 p p K

Answer: D

💡 Solution & Explanation

AB2(g) AB(g) + Y2B2(g) Initial moles 0 Moles at equ. 1-x x x ;    n x M.F. x x   x x       2 x 2 x M.F. x x P.P p px 1 p kp = p p p x x  = x p 3 x3 = p K p x3 = p K 2 p x = 3 p Kp

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