At temperature T, compound AB2(g) dissociates as AB2(g) AB(g) + 2 1 B2(g) having degree of dissociat — JEE Mains Chemistry Past Papers Chemistry Question
Question
At temperature T, compound AB2(g) dissociates as AB2(g) AB(g) + 2 1 B2(g) having degree of dissociation x (small compared to unity). The correct expression for x in terms of Kp and p is: (A) 3 p p K (B) p K (C) 4 p p K (D) 3 p p K
Answer: D
💡 Solution & Explanation
AB2(g) AB(g) + Y2B2(g) Initial moles 0 Moles at equ. 1-x x x ; n x M.F. x x x x 2 x 2 x M.F. x x P.P p px 1 p kp = p p p x x = x p 3 x3 = p K p x3 = p K 2 p x = 3 p Kp
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