If C(diamond) C(graphite) + X kJ mol–1 C(diamond) + O2(g) CO2(g) + Y kJ mol–1 C(graphite) + O2(g) CO2(g) + Z kJ mol–1 at constant temperature. Then (A) X = – Y + Z (B) X = Y – Z (C) X = Y + Z (D) – X

Question

If C(diamond) C(graphite) + X kJ mol–1 C(diamond) + O2(g) CO2(g) + Y kJ mol–1 C(graphite) + O2(g) CO2(g) + Z kJ mol–1 at constant temperature. Then

(A) X = – Y + Z
(B) X = Y – Z
(C) X = Y + Z
(D) – X = Y + Z

Prashant Kotian · Accepted Answer

Correct answer: B. Ha = – X ; Hb = – X ; Hc = – Z (a) = (b) – (c) X = Y – Z | JEE(Main) 2025 | DATE : 29-01-2025 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 3

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