Wavelength of photon which has energy equal to average of energies of photons with lambda_1 = 4000 A — Atomic Structure Chemistry Question
Question
Wavelength of photon which has energy equal to average of energies of photons with lambda_1 = 4000 Angstrom and lambda_2 = 6000 Angstrom will be
Answer: B
💡 Solution & Explanation
1/λ = 0.5*(1/lambda1 + 1/lambda2). λ = 2*lambda1*lambda2/(lambda1+lambda2) = 2*4000*6000/10000 = 4800 Angstrom.
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