A metallic element exists as cubic lattice. Each edge of the unit cell is 4.0 Å. The density of the — Solid State Chemistry Question
Question
A metallic element exists as cubic lattice. Each edge of the unit cell is 4.0 Å. The density of the metal is 6.25 g/cm³. How many unit cells will be present in 100 g of the metal?
Answer: B
💡 Solution & Explanation
Volume of one unit cell V = a^3 = (4.0 × 10^-8 cm)^3 = 6.4 × 10^-23 cm³. Density (ρ) = 6.25 g/cm³. Total volume of 100 g of metal = Mass / Density = 100 g / 6.25 g/cm³ = 16 cm³. Total number of unit cells = Total volume / Volume of one unit cell = 16 cm³ / (6.4 × 10^-23 cm³) = 2.5 × 10^23.
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