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AITS & Test SerieshardNUMERICAL

Question

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Answer: 579

💡 Solution & Explanation

Q = It 190.5 g Cu = 3 mole ½ mole Cu deposited by 1 F 3 mole Cu deposited = 6 F = 6  96500 = 579000 coulomb  x = 579000 Then x  10–3 = 579

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