Correct answer: 4.   a 1 pH pK logC 2   =     3 1 1 5 log10 5 3 4 2 2     

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 4

💡 Solution & Explanation

  a 1 pH pK logC 2   =     3 1 1 5 log10 5 3 4 2 2     

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