See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

      A aq 2B aq C aq t 0 a 0 0 a a t 10 min a a 2 2 3a 3a 3a t 20 min a 4 2 4 t 0 2a a         Let the normality of ‘T’ is N and initial volume of ‘T’ is used x ml At t = 0 Meq. of A = Meq. of T a 2n N x    … (1) At t = 10 min Meq. of (A + B + C) = Meq. of T a a 2n a n 2n 40 N 2 2        … (2) At t = 20 min Meq. of (A + B + C) = Meq. of T a 3a 3a 2n n 2n N y 4 2 4        … (3) At t =  min Meq. of (B + C) = Meq. of T 2a n a 2n N z      … (4) Solving these equilibrium 80 140 160 x ml, y ml,z ml 3 3 3    Value of y z