0.01 mole of H3POx is completely neutralised by 0.56 gram of KOH hence : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Calculate the moles of KOH used: 0.56 g / 56.1 g/mol = 0.01 mol. Step 2: The mole ratio of H3PO_x to KOH is 0.01 : 0.01 = 1 : 1, which means one mole of H3PO_x releases one mole of H+ ions (monobasic). Step 3: Among the phosphorus oxyacids, hypophosphorous acid (H3PO2, x=2) is monobasic. Thus, x = 2 and the acid is monobasic.