A 2.24 l cylinder of oxygen at 0°C and 1 atm is found to develop a leakage. When the leakage was plugged, the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be

Question

Prashant Kotian · Accepted Answer

Correct answer: A. Initial moles of gas n1 = 2.24 / 22.4 = 0.10 mol. Final pressure P2 = 570 / 760 = 0.75 atm. Since V and T are constant, n2 = n1 * (P2 / P1) = 0.10 * 0.75 = 0.075 mol. Moles of gas that escaped = n1 - n2 = 0.10 - 0.075 = 0.025 mol.

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