2 2 2MnO bI cH O xI yMnO zOH If the above equation is balanced with integer coefficients, the value — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Reduction Half Oxidation Half 2 2MnO 2MnO  2I I 2e     2 2MnO 4H O 6e 2MnO 8OH        6I 3I 6e     Adding oxidation half and reduction half, net reaction is 2 2 2MnO 6I 4H O 3I 2MnO 8OH          z = 8  Ans 8