Correct answer: B.    3 2 CaCO s CaO s CO g    2 p CO K P  Gº = 130.2 kJ mol–1 = –2.303RT log Kp p 130.2 logK

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

   3 2 CaCO s CaO s CO g    2 p CO K P  Gº = 130.2 kJ mol–1 = –2.303RT log Kp p 130.2 logK

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