See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  2 x 2 2 0 f x f t 1 dt 1 x 1 t         f 0 1  Differentiate        2 2 2 2 2 1 x f ' x 2x f x f x 1 x 1 x       2 2 dy 2x .y y dx 1 x     L.D.E   2 2 1 dy 2x 1 1 dx y y 1 x     Put 1 T y     2 3 3 1 x f x x 3x 3       Answer is 15 17