Conductivity of water (in Ω^-1 cm^-1) is — Electrochemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Recall the cell constant from Q13.** From the calibration: Cell constant $G^* = 0.4\ \text{cm}^{-1}$ **Step 2: Measure the conductivity of pool water.** The pool water sample has resistance $R_{\text{water}} = 10{,}000\ \Omega$. **Step 3: Calculate conductivity of water.** $$\kappa_{\text{water}} = \frac{G^*}{R_{\text{water}}} = \frac{0.4}{10{,}000} = 4 \times 10^{-5}\ \Omega^{-1}\text{cm}^{-1} = 0.00004\ \Omega^{-1}\text{cm}^{-1}$$ $$\boxed{\text{Answer: D — } \kappa_{\text{water}} = 4 \times 10^{-5} = 0.00004\ \Omega^{-1}\text{cm}^{-1}}$$