The magnetic moment of a complex ion is 2.83 BM. The complex ion is : — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: A spin-only magnetic moment of 2.83 BM corresponds to exactly 2 unpaired electrons (\sqrt{2(2+2)} = \sqrt{8} ≈ 2.83 BM). Step 2: Determine the number of unpaired electrons in each complex ion: V^3+ is 3d^2 (n = 2); Cr^3+ is 3d^3 (n = 3); Cu^2+ is 3d^9 (n = 1); Mn^2+ is 3d^5 (n = 5). Step 3: Since only [V(H2O)6]^3+ has exactly 2 unpaired electrons, it matches the given magnetic moment of 2.83 BM, corresponding to option (a).