The ratio of root mean square speed of at 50 K and that of at 800 K is — States of Matter and Gaseous State Chemistry Question
Question
The ratio of root mean square speed of $H_2$ at 50 K and that of $O_2$ at 800 K is
Answer: C
💡 Solution & Explanation
u_rms = √(3RT/M) => u_H2/u_O2 = sqrt[(T_H2/M_H2) * (M_O2/T_O2)] = sqrt[(50/2) * (32/800)] = √(25 * 0.04) = 1 .
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