See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Replacing x by 2 x we get, 10 r 20 20 20 20 10 2 10 r 20 r r r 10 20 r r r r r 2 r 0 r 0 r 0 r 0 8 8 2 4 a 2 (2x 3x 4) a 2 x a x a 2 x x x x                                 Comparing coefficient x7 both sides, we get 3 7 13 a a 2 .   For More Material Join: @JEEAdvanced_2024 AITS-FT-III (Paper-2)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12 SECTION – C