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The increasing order of pK for the following compounds will be : i) H N–CH=NH ii) iii) CH NHCH b 2 3Amines Chemistry Question

Question

The increasing order of pK for the following compounds will be : i) H N–CH=NH ii) iii) CH NHCH b 2 3 3 2 o 3 b (A) ii < iii < i (B) iii < i < ii (C) i < ii < iii (D) ii < i < iii

Answer: B) III < I < II

💡 Solution & Explanation

Weaker the conjugate acid, stronger the base. (ii) is the most basic as it has a guanidine like Structure. It has a high tendency of accepting a proton, giving rise to a very stable conjugate acid and hence, is a very strong base.In compound (i), the N is sp hybridised and its electronegativity is higher as compared to the compound (iii) which is a 2 amine (sp hybridised). So compound (ii) is more basic compared to compound (iii). So the order of basicity is ii > i > iii and thus the order of pK value will be iii > i > ii

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