See image — AITS & Test Series Chemistry Question
Question
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Answer: C
💡 Solution & Explanation
Milliequivalent of H2SO4 = 25.1 x 0.02 = 0.502 Equivalent = 0.502 x 10-3 Eq of H2SO4 = Eq of CaCO3 Mass of CaCO3 = Eq x 50 = 0.502 x 10-3 x 50 = 0.0251 100 mL H2O = 100 g contains 0.0251 g CaCO3 106 g of water will contain 6 2
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