The number of neutrons accompanying the formation of and from the absorption of slow neutron by by n — Nuclear Chemistry and Radioactivity Chemistry Question
Question
The number of neutrons accompanying the formation of ${}_{54}\text{Xe}^{139}$ and ${}_{38}\text{Sr}^{94}$ from the absorption of slow neutron by ${}_{92}\text{U}^{235}$ by nuclear fission is
Answer: D
💡 Solution & Explanation
The balanced fission reaction is ${}_{92}\text{U}^{235} + {}_0\text{n}^1 \to {}_{54}\text{Xe}^{139} + {}_{38}\text{Sr}^{94} + x {}_0\text{n}^1$. Equating mass numbers: $235 + 1 = 139 + 94 + x \implies 236 = 233 + x \implies x = 3$. Therefore, correct answer is D.
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