The of is 8.0 h. It undergoes decay to its daughter (unstable) element of half-life 60.0 minute. The — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

Using the formula $t_{max} = \frac{\ln(\lambda_2 / \lambda_1)}{\lambda_2 - \lambda_1}$. $t_1 = 480 \text{ min}$, $t_2 = 60 \text{ min}$. $t_{max} = \frac{\ln(480/60)}{(\ln 2)/60 - (\ln 2)/480} = \frac{\ln 8}{(0.693) \cdot (7/480)} = \frac{2.079 \cdot 480}{0.693 \cdot 7} \approx 205.7 \text{ min}$. Therefore, correct answer is A.