Two isotopes 'P' and 'Q' of atomic masses 10 and 20, respectively, are mixed in equal amount, by mas — Nuclear Chemistry and Radioactivity Chemistry Question
Question
Two isotopes 'P' and 'Q' of atomic masses 10 and 20, respectively, are mixed in equal amount, by mass. After 20 day, their mass ratio is found to be 1:4. Isotope 'P' has a half-life of 10 days. The half-life of isotope 'Q' is
Answer: D
💡 Solution & Explanation
Let initial masses be $m_0$. After 20 days (2 half-lives for P), P's remaining mass is $m_0/4$. Mass ratio $P:Q$ becomes $(m_0/4) : m_Q = 1:4$, yielding $m_Q = m_0$. Q's mass did not decrease, meaning it did not decay. Thus, its half-life is infinite. Therefore, correct answer is D.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes