is the more stable isotope of Na. Find out the process by which can undergo radioactive decay — Nuclear Chemistry and Radioactivity Chemistry Question
Question
$\text{Na}^{23}$ is the more stable isotope of Na. Find out the process by which $\text{Na}^{24}$ can undergo radioactive decay
Answer: A
💡 Solution & Explanation
$\text{Na}^{24}$ is neutron-rich compared to the stable $\text{Na}^{23}$. To achieve stability, it will convert a neutron into a proton by emitting a beta particle. Therefore, correct answer is A.
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