A positron is emitted from . The ratio of the atomic mass and atomic number in the resulting nuclide β Nuclear Chemistry and Radioactivity Chemistry Question
Question
A positron is emitted from ${}_{11}\text{Na}^{23}$. The ratio of the atomic mass and atomic number in the resulting nuclide is
Answer: C
π‘ Solution & Explanation
Positron emission decreases the atomic number by 1 (from 11 to 10, forming Neon) while the mass number remains 23. The new nuclide is ${}_{10}\text{Ne}^{23}$, so the ratio is 23/10. Therefore, correct answer is C.
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