Nuclear Chemistry and RadioactivitymediumMCQ SINGLE

A positron is emitted from . The ratio of the atomic mass and atomic number in the resulting nuclideNuclear Chemistry and Radioactivity Chemistry Question

Question

A positron is emitted from ${}_{11}\text{Na}^{23}$. The ratio of the atomic mass and atomic number in the resulting nuclide is

Answer: C

💡 Solution & Explanation

Positron emission decreases the atomic number by 1 (from 11 to 10, forming Neon) while the mass number remains 23. The new nuclide is ${}_{10}\text{Ne}^{23}$, so the ratio is 23/10. Therefore, correct answer is C.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry