Which stable nucleus has radius half of the radius of nucleus of ? — Nuclear Chemistry and Radioactivity Chemistry Question
Question
Which stable nucleus has radius half of the radius of nucleus of $\text{Fe}^{56}$?
Answer: D
💡 Solution & Explanation
The radius of a nucleus is proportional to $A^{1/3}$. For $R_1/R_2 = 1/2$, we must have $A_1/A_2 = (1/2)^3 = 1/8$. Since $A_2 = 56$, $A_1 = 56/8 = 7$. The nucleus with mass number 7 is $\text{Li}^{7}$. Therefore, correct answer is D.
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