Which stable nucleus has radius half of the radius of nucleus of ? β Nuclear Chemistry and Radioactivity Chemistry Question
Question
Which stable nucleus has radius half of the radius of nucleus of $\text{Fe}^{56}$?
Answer: D
π‘ Solution & Explanation
The radius of a nucleus is proportional to $A^{1/3}$. For $R_1/R_2 = 1/2$, we must have $A_1/A_2 = (1/2)^3 = 1/8$. Since $A_2 = 56$, $A_1 = 56/8 = 7$. The nucleus with mass number 7 is $\text{Li}^{7}$. Therefore, correct answer is D.
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes