Nuclear Chemistry and RadioactivitymediumMCQ MULTIPLE

Assuming that only particles emitted during natural radioactive decay are alpha and beta particles, Nuclear Chemistry and Radioactivity Chemistry Question

Question

Assuming that only particles emitted during natural radioactive decay are alpha and beta particles, which of the following atoms could not possibly result from the natural decay of ${}_{92}\text{U}^{235}$ atoms?

Answer: C

💡 Solution & Explanation

Natural decay sequences involve changes in mass number only by multiples of 4 (due to alpha particles). To form ${}_{89}\text{Ac}^{235}$ from ${}_{92}\text{U}^{235}$, the mass number must remain the same (zero alpha decays). This would require 3 positron emissions or electron captures to reduce the atomic number by 3, but the question specifies only alpha and beta ($\beta^-$) particles are emitted. Standard beta emission would increase, not decrease, the atomic number. Therefore, correct answer is C.

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