If , the limiting value of as is — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

From the equation $N = 2N_o - N_oe^{-\lambda t}$, as $t \to \infty$, the term $e^{-\lambda t}$ approaches $0$. The steady-state (limiting) value is $2N_o - 0 = 2N_o$. Therefore, correct answer is D.