If the atomic number of 'H' is 88, what is the atomic number of 'A'? — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

The series comprises 4 $\alpha$-decays and 3 $\beta$-decays. Total atomic number change $\Delta Z = 4(-2) + 3(+1) = -8 + 3 = -5$. If $Z_H = 88$, then $Z_A = 88 - (-5) = 93$. Therefore, correct answer is C.